(All values in metres unless otherwise indicated)
LINE |
BF |
IS |
FS |
HPC |
INITIAL RL |
ADJ. (mm) |
ADJ. RL |
REMARKS |
| 1 | 1.717 | 30.947 | 29.23 | - | 29.23 | OBM 1 RL 29.23m AOD | ||
| 2 | 1.432 | 29.515 | -2 | 29.51 | A | |||
| 3 | 2.918 | 1.716 | 32.149 | 29.231 | -2 | 29.23 | B(CP) | |
| 4 | 2.272 | 29.877 | -4 | 29.87 | C | |||
| 5 | 0.816 | 0.953 | 32.012 | 31.196 | -4 | 31.19 | D(CP) | |
| 6 | 1.436 | 3.005 | 30.443 | 29.007 | -6 | 29.00 | E(CP) | |
| 7 | 1.246 | 1.391 | 30.298 | 29.052 | -8 | 29.04 | CP | |
| 8 | 1.353 | 28.945 | -10 | 28.93 | F | |||
| 9 | 1.462 | 28.836 | -10 | 28.83 | G | |||
| 10 | 0.628 | 29.670 | -10 | 29.66 | OBM 2 RL 29.66m AOD | |||
| 8.133 | 7.693 |
The RLs were calculated using the following procedure.
1) For level position I1 = RL of OBM1 + staff reading at OBM1
= 29.23 + 1.717
= 30.947 m
RL of A = HPC at I1 - staff reading at A
= 30.947 - 1.432
= 29.515 m
RL of B = 30.947 - 1.716
= 29.231 m
2) B is a change point, it is necessary to calculate new HPC for position I2
HPC at I2 = RL of B + staff reading at B from I2
= 29.231 + 2.918
= 32.149 m
RL of C = 32.149 - 2.272
= 29.877 m
RL of D = 32.149 - 0.953
= 31.196 m
3) The procedure is repeated for positions I3,I4 and I5 until the RL of OBM 2 is calculated.
4) The calculations must be checked then. For the HPC method, the check is
Total of FS - Total of BS = Known RL of start point -
calculated initial RL of end point
For this example,
Total of FS - Total of BS = 7.693 - 8.133 = -0.440 m
Known RL of start point - calculated initial RL of end point
= 29.23 - 29.670
= -0.440 m
If the check is not satisfied exactly then the calculations are in error and
should be repeated.